Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:36Z
11t² + 7t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
198K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
CH₄ + 2O₂ → CO₂ + 2H₂O
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 3 1 ; 7 4 | = 5
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 5 3 ; 7 6 | = 9
176K
det| 7 4 ; 4 8 | = 40
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
ΔS ≥ 0
det| 10 1 ; 4 11 | = 106
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2