Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 15:03Z
d/dz [z^3] = 3z^2
∑_{k=1}^{n} k = n(n+1)/2
75K
6φ² + 8φ + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
276K
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 7 4 ; 4 8 | = 40
390K
det| 10 8 ; 7 11 | = 54
det| 7 9 ; 1 8 | = 47
153K
det| 5 6 ; 2 6 | = 18
7θ² + 9θ + 3 = 0
iħ ∂ψ/∂t = Ĥψ