Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:09Z
d/dα [α^11] = 11α^10
\frac{3}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
392K
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
330K
10r² + 3r + 0 = 0
det| 9 4 ; 1 10 | = 86
375K
e^{i\pi} + 1 = 0
E = mc²
N₂ + 3H₂ ⇌ 2NH₃
det| 3 9 ; 0 4 | = 12
e^{i\pi} + 1 = 0