Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 17:01Z
∑_{k=1}^{n} k = n(n+1)/2
8β² + 2β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 11 9 ; 0 12 | = 132
390K
\lim_{r\to 0} \frac{\sin r}{r} = 1
det| 11 4 ; 5 12 | = 112
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det| 12 1 ; 1 13 | = 155
det| 3 3 ; 4 4 | = 0
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d/dy [y^11] = 11y^10
188K