Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:11Z
det| 2 2 ; 6 3 | = -6
det| 9 4 ; 1 10 | = 86
326K
∑_{k=1}^{n} k = n(n+1)/2
198K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 1 ; 4 4 | = 8
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
319K
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
10φ² + 7φ + 2 = 0