Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:14Z
7φ² + 4φ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
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e^{i\pi} + 1 = 0
det| 3 1 ; 7 4 | = 5
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det| 7 2 ; 7 8 | = 42
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 5 3 ; 7 6 | = 9
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det| 4 6 ; 4 5 | = -4
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d/dβ [β^2] = 2β^1
d/dy [y^11] = 11y^10
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