Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:40Z
det| 3 3 ; 5 4 | = -3
∑_{k=1}^{n} k = n(n+1)/2
75K
∇²β = 0
det| 3 1 ; 7 4 | = 5
129K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
390K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
1K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 4 4 ; 5 5 | = 0
338K
det| 3 7 ; 2 4 | = -2