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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 23:23Z

11t² + 7t + 4 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

326K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

198K

E = mc²

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

155K

CaCO₃ → CaO + CO₂

63K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

N₂ + 3H₂ ⇌ 2NH₃

366K

∑_{k=1}^{n} k = n(n+1)/2

201K

det| 7 4 ; 4 8 | = 40

176K

6t² + 6t + 4 = 0

319K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

359K

PV = nRT

263K

ω = 2πf

233K

∫₀^∞ e^(-φ²) dφ = √π / 2

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