Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 14:04Z
∫₀^∞ e^(-ψ²) dψ = √π / 2
e^{i\pi} + 1 = 0
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-t²) dt = √π / 2
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\lim_{t\to 0} \frac{\sin t}{t} = 1
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
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∫₀^∞ e^(-β²) dβ = √π / 2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 7 2 ; 3 8 | = 50
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det| 10 2 ; 7 11 | = 96
5n² + 6n + 5 = 0