Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:08Z
11t² + 7t + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
326K
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
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CH₄ + 2O₂ → CO₂ + 2H₂O
det| 11 9 ; 0 12 | = 132
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 7 4 ; 4 8 | = 40
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