Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 13:25Z
2α² + 5α + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
479K
iħ ∂ψ/∂t = Ĥψ
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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9φ² + 5φ + 2 = 0
d/dω [ω^2] = 2ω^1
CH₄ + 2O₂ → CO₂ + 2H₂O
CH₄ + 2O₂ → CO₂ + 2H₂O
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∑_{k=1}^{n} k = n(n+1)/2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
10α² + 1α + 0 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
N₂ + 3H₂ ⇌ 2NH₃