Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 15:24Z
\lim_{y\to 0} \frac{\sin y}{y} = 1
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-ψ²) dψ = √π / 2
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det| 8 8 ; 0 9 | = 72
\lim_{α\to 0} \frac{\sin α}{α} = 1
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λ = h/p
AgNO₃ + NaCl → AgCl↓ + NaNO₃
8x² + 1x + 3 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
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