Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:46Z
d/dα [α^11] = 11α^10
∑_{k=1}^{n} k = n(n+1)/2
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\frac{3}{5} \sum_{i=1}^{n} i^{2}
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
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det| 9 4 ; 1 10 | = 86
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10r² + 3r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
412K