Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 23:16Z
d/dα [α^11] = 11α^10
∑_{k=1}^{n} k = n(n+1)/2
234K
\frac{3}{5} \sum_{i=1}^{n} i^{2}
λ = h/p
det| 3 6 ; 0 4 | = 12
100K
∑_{k=1}^{n} k = n(n+1)/2
330K
10r² + 3r + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
375K
det| 4 4 ; 5 5 | = 0
139K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
412K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
28K
det| 3 9 ; 0 4 | = 12
e^{i\pi} + 1 = 0