Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:14Z
∑_{k=1}^{n} k = n(n+1)/2
det| 6 6 ; 3 7 | = 24
75K
det| 5 6 ; 2 6 | = 18
479K
3β² + 6β + 2 = 0
F = ma
∑_{k=1}^{n} k = n(n+1)/2
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
CH₄ + 2O₂ → CO₂ + 2H₂O
1K
1x² + 5x + 7 = 0
det| 11 4 ; 5 12 | = 112
473K
det| 9 4 ; 1 10 | = 86
338K
∇²ψ = 0
det| 5 2 ; 3 6 | = 24
188K
det| 3 3 ; 4 4 | = 0
416K
3φ² + 8φ + 6 = 0