Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
det| 1 4 ; 3 2 | = -10
276K
F = ma
det| 3 1 ; 7 4 | = 5
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 3 3 ; 4 4 | = 0
153K
1x² + 5x + 7 = 0
det| 5 6 ; 7 6 | = -12
473K
∇²ψ = 0