Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:36Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 9 ; 1 8 | = 47
479K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
det| 9 4 ; 1 10 | = 86
129K
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 11 9 ; 5 12 | = 87
153K
det| 5 3 ; 7 6 | = 9
473K