Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:38Z
11t² + 7t + 4 = 0
∫₀^∞ e^(-x²) dx = √π / 2
326K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
198K
E = mc²
det| 7 4 ; 4 8 | = 40
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 1 4 ; 3 2 | = -10
366K
∑_{k=1}^{n} k = n(n+1)/2
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 1 4 ; 0 2 | = 2
176K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 10 1 ; 4 11 | = 106
\binom{n}{k} = \frac{n!}{k!(n-k)!}
233K
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ