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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 23:34Z

11t² + 7t + 4 = 0

∇ × E = −∂B/∂t

326K

10ω² + 7ω + 4 = 0

198K

E = mc²

det| 4 8 ; 3 5 | = -4

155K

det| 7 2 ; 7 8 | = 42

63K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

366K

ω = 2πf

201K

5r² + 7r + 0 = 0

176K

3ω² + 2ω + 2 = 0

319K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K

det| 9 4 ; 1 10 | = 86

263K

d/dt [t^3] = 3t^2

233K

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