Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:21Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
75K
∫₀^∞ e^(-t²) dt = √π / 2
479K
11n² + 1n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 1 ; 7 4 | = 5
390K
4y² + 8y + 1 = 0
det| 11 7 ; 4 12 | = 104
det| 11 9 ; 1 12 | = 123
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf
det| 5 2 ; 2 6 | = 26