Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:25Z
11t² + 7t + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
326K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
198K
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 10 7 ; 3 11 | = 89
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CH₄ + 2O₂ → CO₂ + 2H₂O
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 10 1 ; 4 11 | = 106
det| 9 4 ; 1 10 | = 86
233K
\lim_{t\to 0} \frac{\sin t}{t} = 1
412K