Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:56Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
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F = ma
det| 3 7 ; 2 4 | = -2
191K
det| 12 1 ; 4 13 | = 152
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 9 ; 7 6 | = -33
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