Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:21Z
11t² + 7t + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 7 2 ; 7 8 | = 42
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{β\to 0} \frac{\sin β}{β} = 1
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
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