Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:55Z
∑_{k=1}^{n} k = n(n+1)/2
det| 1 4 ; 3 2 | = -10
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3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
1x² + 5x + 7 = 0
det| 9 4 ; 1 10 | = 86
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