Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:18Z
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
479K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
129K
F = ma
det| 11 9 ; 5 12 | = 87
191K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
390K
det| 9 4 ; 1 10 | = 86
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∫₀^∞ e^(-t²) dt = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
188K
CH₄ + 2O₂ → CO₂ + 2H₂O
416K