Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:06Z
det| 2 2 ; 6 3 | = -6
∑_{k=1}^{n} k = n(n+1)/2
326K
det| 4 6 ; 4 5 | = -4
198K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 3 1 ; 4 4 | = 8
det| 3 3 ; 4 4 | = 0
201K
ΔS ≥ 0
det| 9 4 ; 1 10 | = 86
176K
∑_{k=1}^{n} k = n(n+1)/2
319K
∇ × E = −∂B/∂t
10φ² + 7φ + 2 = 0