Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
479K
3β² + 6β + 2 = 0
det| 5 6 ; 7 6 | = -12
129K
F = ma
CH₄ + 2O₂ → CO₂ + 2H₂O
191K
det| 4 4 ; 5 5 | = 0
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 5 6 ; 2 6 | = 18
153K
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
473K