Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 12:44Z
2ψ² + 5ψ + 4 = 0
det| 7 4 ; 4 8 | = 40
75K
N₂ + 3H₂ ⇌ 2NH₃
det| 4 6 ; 4 5 | = -4
276K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
129K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
det| 3 7 ; 2 4 | = -2
191K
CH₄ + 2O₂ → CO₂ + 2H₂O
390K
∇²z = 0
∑_{k=1}^{n} k = n(n+1)/2
1K
N₂ + 3H₂ ⇌ 2NH₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8t² + 2t + 3 = 0