Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:52Z
det| 3 3 ; 5 4 | = -3
det| 5 6 ; 7 6 | = -12
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∑_{k=1}^{n} k = n(n+1)/2
479K
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
191K
det| 7 4 ; 4 8 | = 40
390K
E = mc²
∫₀^∞ e^(-t²) dt = √π / 2
153K
AgNO₃ + NaCl → AgCl↓ + NaNO₃