Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:41Z
det| 3 3 ; 5 4 | = -3
det| 7 4 ; 4 8 | = 40
75K
∇²β = 0
det| 5 6 ; 7 6 | = -12
276K
e^{i\pi} + 1 = 0
det| 7 9 ; 1 8 | = 47
191K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
1K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
473K
det| 3 7 ; 2 4 | = -2
det| 1 4 ; 3 2 | = -10
188K
∂t/∂β = 2t