Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:29Z
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
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\frac{8}{9} \sum_{i=1}^{n} i^{2}
det| 4 8 ; 3 5 | = -4
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det| 11 9 ; 0 12 | = 132
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F = ma
∑_{k=1}^{n} k = n(n+1)/2
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10n² + 4n + 5 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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