Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:23Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
det| 4 4 ; 5 5 | = 0
129K
F = ma
det| 10 2 ; 1 11 | = 108
191K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 9 4 ; 1 10 | = 86
153K
1x² + 5x + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
473K
∇²ψ = 0