Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 16:26Z
∇ × E = −∂B/∂t
\frac{8}{9} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
129K
F = ma
\oint_C \vec{F}\cdot d\vec{r} = 0
191K
10n² + 4n + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
153K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
12x² + 6x + 5 = 0
∫₀^∞ e^(-γ²) dγ = √π / 2