Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 22:04Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
278K
3β² + 9β + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
233K
ω = 2πf
∫₀^∞ e^(-ψ²) dψ = √π / 2
139K
∫₀^∞ e^(-x²) dx = √π / 2
412K
det| 9 4 ; 1 10 | = 86
223K
det| 1 4 ; 3 2 | = -10
385K