Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-21 11:03Z
d/dβ [β^10] = 10β^9
det| 2 5 ; 1 3 | = 1
∫₀^∞ e^(-x²) dx = √π / 2
143K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
434K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∑_{k=1}^{n} k = n(n+1)/2
63K
5t² + 1t + 5 = 0
det| 7 4 ; 4 8 | = 40
39K
iħ ∂ψ/∂t = Ĥψ
N₂ + 3H₂ ⇌ 2NH₃