Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:39Z
11t² + 7t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
326K
CH₄ + 2O₂ → CO₂ + 2H₂O
198K
E = mc²
det| 7 2 ; 7 8 | = 42
155K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
CH₄ + 2O₂ → CO₂ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
319K
∑_{k=1}^{n} k = n(n+1)/2
263K
det| 7 4 ; 4 8 | = 40
233K