Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-18 18:47Z
11γ² + 9γ + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
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λ = h/p
5θ² + 1θ + 3 = 0
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∇ × E = −∂B/∂t
∇ × E = −∂B/∂t
\lim_{α\to 0} \frac{\sin α}{α} = 1
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂