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Math Dump /sym/7fd97a

id=1 · host=jp.commstar.world · 2026-10-19 23:43Z

11t² + 7t + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

326K

12n² + 2n + 2 = 0

198K

E = mc²

∂ψ/∂β = 4ψ

155K

CH₄ + 2O₂ → CO₂ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

366K

det| 9 4 ; 1 10 | = 86

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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CH₄ + 2O₂ → CO₂ + 2H₂O

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∫₀^∞ e^(-ψ²) dψ = √π / 2

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∑_{k=1}^{n} k = n(n+1)/2

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10t² + 9t + 5 = 0

233K

d/dt [t^3] = 3t^2

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