Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 08:11Z
∑_{k=1}^{n} k = n(n+1)/2
det| 11 5 ; 0 12 | = 132
75K
det| 7 4 ; 4 8 | = 40
479K
11n² + 1n + 0 = 0
∫₀^∞ e^(-t²) dt = √π / 2
276K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
129K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 7 6 ; 1 8 | = 50
191K
4y² + 8y + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
1K
det| 11 7 ; 4 12 | = 104
det| 11 9 ; 1 12 | = 123
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf
det| 5 2 ; 2 6 | = 26