Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:31Z
∑_{k=1}^{n} k = n(n+1)/2
3β² + 6β + 2 = 0
F = ma
det| 10 9 ; 0 11 | = 110
191K
det| 4 6 ; 4 5 | = -4
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
153K
det| 5 2 ; 3 6 | = 24
473K