Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:19Z
11t² + 7t + 4 = 0
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
366K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 11 9 ; 5 12 | = 87
359K
det| 9 4 ; 1 10 | = 86
263K
det| 10 1 ; 4 11 | = 106
∑_{k=1}^{n} k = n(n+1)/2
233K