Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 02:29Z
det| 2 2 ; 6 3 | = -6
det| 3 6 ; 0 4 | = 12
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∑_{k=1}^{n} k = n(n+1)/2
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
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det| 3 1 ; 4 4 | = 8
det| 7 4 ; 4 8 | = 40
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det| 4 4 ; 5 5 | = 0
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ΔS ≥ 0
∇ × E = −∂B/∂t
det| 4 8 ; 3 5 | = -4
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