Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:40Z
11t² + 7t + 4 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
201K
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
319K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 9 4 ; 1 10 | = 86
359K
∑_{k=1}^{n} k = n(n+1)/2
263K