Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:21Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
F = ma
det| 12 1 ; 4 13 | = 152
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\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
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1x² + 5x + 7 = 0
det| 10 9 ; 0 11 | = 110
473K