Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 16:46Z
7φ² + 4φ + 5 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
det| 9 4 ; 1 10 | = 86
63K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
366K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∫₀^∞ e^(-x²) dx = √π / 2
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d/dβ [β^2] = 2β^1