Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 05:22Z
det| 3 3 ; 5 4 | = -3
∫₀^∞ e^(-t²) dt = √π / 2
75K
∇²β = 0
e^{i\pi} + 1 = 0
det| 3 1 ; 7 4 | = 5
191K
det| 3 7 ; 2 4 | = -2
390K
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
E = mc²
det| 3 7 ; 2 4 | = -2