Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:29Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
75K
3β² + 6β + 2 = 0
det| 7 4 ; 4 8 | = 40
276K
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
191K
∑_{k=1}^{n} k = n(n+1)/2
153K
CH₄ + 2O₂ → CO₂ + 2H₂O
473K