Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 23:09Z
11t² + 7t + 4 = 0
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
155K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
63K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
366K
CH₄ + 2O₂ → CO₂ + 2H₂O
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∫₀^∞ e^(-ψ²) dψ = √π / 2
359K
det| 10 1 ; 4 11 | = 106
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
233K
\lim_{α\to 0} \frac{\sin α}{α} = 1
412K
∑_{k=1}^{n} k = n(n+1)/2