Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-20 01:34Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
479K
3β² + 6β + 2 = 0
F = ma
det| 7 4 ; 4 8 | = 40
191K
det| 10 4 ; 1 11 | = 106
390K
\frac{8}{7} \sum_{i=1}^{n} i^{2}
det| 7 9 ; 1 8 | = 47
153K
1x² + 5x + 7 = 0