Math Dump /sym/7fd97a
id=1 · host=jp.commstar.world · 2026-10-19 18:27Z
∇²α = 0
6φ² + 8φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
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∂φ/∂φ = 1φ
∑_{k=1}^{n} k = n(n+1)/2
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∑_{k=1}^{n} k = n(n+1)/2
359K
det| 7 4 ; 4 8 | = 40
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∫₀^∞ e^(-φ²) dφ = √π / 2
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